3次元調和振動子/メモ の履歴(No.4)
更新$n=2$ の場合†
であり、
であるから、
&math( &\varphi_{200}\propto \left(-1+\frac{2}{3}\frac{r^2}{r_2^2}\right) 2 \sqrt{\pi}\,Y_{0}^{0}
- \frac{4}{3} \sqrt{\frac{\pi }{5}} \frac{r^2}{r_2^2} Y_{2}^{0}
- 2 \sqrt{\frac{2 \pi }{15}} \frac{r^2}{r_2^2} (Y_{2}^{-2}+Y_{2}^{2}) \\ &\varphi_{020}\propto \left(-1+\frac{2}{3}\frac{r^2}{r_2^2}\right) 2 \sqrt{\pi }\,Y_{0}^{0}
- \frac{4}{3} \sqrt{\frac{\pi }{5}} \frac{r^2}{r_2^2} Y_{2}^{0}
- 2 \sqrt{\frac{2 \pi }{15}} \frac{r^2}{r_2^2} (Y_{2}^{-2}+Y_{2}^{2}) \\ &\varphi_{002}\propto \left(-1+\frac{2}{3}\frac{r^2}{r_2^2}\right) 2 \sqrt{\pi }\,Y_{0}^{0}
- \frac{8}{3} \sqrt{\frac{\pi }{5}} \frac{r^2}{r_2^2} Y_{2}^{0} \\ &\varphi_{110}\propto
- i 2 \sqrt{\frac{\pi }{30}} \frac{r^2}{r_2^2}(Y_{2}^{2}-Y_{2}^{-2}) \\ &\varphi_{101}\propto i 2 \sqrt{\frac{\pi }{30}} \frac{r^2}{r_2^2}(Y_{2}^{-1}+Y_{2}^{1}) \\ &\varphi_{011}\propto 2 \sqrt{\frac{\pi }{30}} \frac{r^2}{r_2^2}(Y_{2}^{-1}-Y_{2}^{1}) \\ );
として、 と、 との線形結合で を表せる。
これを逆に解けば と、 とを で表すこともできる。
LANG:mathematica -1 + 2 ( r Cos[p] Sin[t])^2 == 2 Sqrt[\[Pi]] (-1 + (2 r^2)/3) Y[0, 0] + 2 Sqrt[(2 \[Pi])/15] r^2 (Y[2, 2] + Y[2, -2]) - 4/3 Sqrt[\[Pi]/5] r^2 Y[2, 0] // FullSimplify -1 + 2 ( r Sin[p] Sin[t])^2 == 2 Sqrt[\[Pi]] (-1 + (2 r^2)/3) Y[0, 0] - 2 Sqrt[(2 \[Pi])/15] r^2 (Y[2, 2] + Y[2, -2]) - 4/3 Sqrt[\[Pi]/5] r^2 Y[2, 0] // FullSimplify -1 + 2 ( r Cos[t])^2 == 2 Sqrt[\[Pi]] (-1 + (2 r^2)/3) Y[0, 0] + 8/3 Sqrt[\[Pi]/5] r^2 Y[2, 0] // FullSimplify Sin[p] Cos[p] Sin[t]^2 == -I 2 Sqrt[\[Pi]/30] (Y[2, 2] - Y[2, -2]) // FullSimplify Sin[p] Sin[t] Cos[t] == I 2 Sqrt[\[Pi]/30] (Y[2, 1] + Y[2, -1]) // FullSimplify Cos[p] Sin[t] Cos[t] == 2 Sqrt[\[Pi]/30] (-Y[2, 1] + Y[2, -1]) // FullSimplify
&math(
- 1+2 (r \cos \theta)^2 &= 2 \sqrt{\pi } \left(\frac{2 r^2}{3}-1\right) Y_{0}^{0}
- \frac{8}{3} \sqrt{\frac{\pi }{5}} r^2 Y_{2}^{0} \\
- 1+2 (r \sin \phi \sin \theta)^2 &= 2 \sqrt{\pi } \left(\frac{2 r^2}{3}-1\right) Y_{0}^{0}
- \frac{4}{3} \sqrt{\frac{\pi }{5}} r^2 Y_{2}^{0}
- 2 \sqrt{\frac{2 \pi }{15}} r^2 (Y_{2}^{-2}+Y_{2}^{2}) \\
- 1+2 (r \cos \phi \sin \theta)^2 &= 2 \sqrt{\pi } \left(\frac{2 r^2}{3}-1\right) Y_{0}^{0}
- \frac{4}{3} \sqrt{\frac{\pi }{5}} r^2 Y_{2}^{0}
- 2 \sqrt{\frac{2 \pi }{15}} r^2 (Y_{2}^{-2}+Y_{2}^{2}) \\ \sin \phi \cos \phi \sin ^2\theta &=-i 2 \sqrt{\frac{\pi }{30}} (Y_{2}^{2}-Y_{2}^{-2}) \\ \sin \phi \sin \theta \cos \theta &=i 2 \sqrt{\frac{\pi }{30}} (Y_{2}^{-1}+Y_{2}^{1}) \\ \cos \phi \sin \theta \cos \theta &=2 \sqrt{\frac{\pi }{30}} (Y_{2}^{-1}-Y_{2}^{1}) \\ );
$n=3$ の場合†
&math( &\varphi_{300}\propto \frac{r}{r_3}\cos\phi\sin\theta-\frac{2}{3}\left(\frac{r}{r_3}\cos\phi\sin\theta\right)^3\\ &\varphi_{030}\propto \frac{r}{r_3}\sin\phi\sin\theta-\frac{2}{3}\left(\frac{r}{r_3}\sin\phi\sin\theta\right)^3\\ &\varphi_{003}\propto \frac{r}{r_3}\cos\theta-\frac{2}{3}\left(\frac{r}{r_3}\cos\theta\right)^3\\ &\varphi_{210}\propto \left(\frac{r}{r_3}\right)^3\left\{1-2\left(\frac{r}{r_2}\cos\phi\sin\theta\right)^2\right\}\sin\phi\sin\theta\\ &\varphi_{021}\propto \left(\frac{r}{r_3}\right)^3\left\{1-2\left(\frac{r}{r_2}\sin\phi\sin\theta\right)^2\right\}\cos\theta\\ &\varphi_{102}\propto \left(\frac{r}{r_3}\right)^3\left\{1-2\left(\frac{r}{r_2}\cos\theta\right)^2\right\}\cos\phi\sin\theta\\ &\varphi_{120}\propto \left(\frac{r}{r_3}\right)^3\left\{1-2\left(\frac{r}{r_2}\sin\phi\sin\theta\right)^2\right\}\cos\phi\sin\theta\\ &\varphi_{012}\propto \left(\frac{r}{r_3}\right)^3\left\{1-2\left(\frac{r}{r_2}\cos\theta\right)^2\right\}\sin\phi\sin\theta\\ &\varphi_{201}\propto \left(\frac{r}{r_3}\right)^3\left\{1-2\left(\frac{r}{r_2}\cos\phi\sin\theta\right)^2\right\}\cos\theta\\ &\varphi_{111}\propto \left(\frac{r}{r_3}\right)^3\cos\phi\sin\theta\sin\phi\sin\theta\cos\theta\\ );
がんばって計算すると、
&math( &\varphi_{300}\propto \sqrt{\frac{2\pi}{3}}\left(1-\frac{2}{5}\frac{r^2}{r_3^2}\right)\frac{r}{r_3}(-Y_1^1+Y_1^{-1})
- \frac{2}{5}\sqrt{\frac{\pi }{21}}\frac{r^3}{r_3^3}(-Y_3^1+Y_3^{-1})
- \frac{2}{3}\sqrt{\frac{\pi }{35}}\frac{r^3}{r_3^3}(-Y_3^3+Y_3^{-3})\\ &\varphi_{030}\propto i\sqrt{\frac{2\pi}{3}}\left(1-\frac{2}{5}\frac{r^2}{r_3^2}\right)\frac{r}{r_3}(Y_1^1+Y_1^{-1})
- i\frac{2}{5}\sqrt{\frac{\pi }{21}}\frac{r^3}{r_3^3}(Y_3^1+Y_3^{-1})
- i\frac{2}{3}\sqrt{\frac{\pi }{35}}\frac{r^3}{r_3^3}(Y_3^3+Y_3^{-3})\\ &\varphi_{003}\propto 2 \sqrt{\frac{\pi }{3}}\left(1-\frac{2}{5}\frac{r^2}{r_3^2}\right)\frac{r}{r_3}Y_1^0-\frac{8}{15}\sqrt{\frac{\pi }{7}}\frac{r^3}{r_3^3}Y_3^0\\ &\varphi_{210}\propto i\sqrt{\frac{2\pi}{3}}\left(1-\frac{2}{5}\frac{r^2}{r_3^2}\right)(Y_1^1+Y_1^{-1})
- i\frac{2}{5}\sqrt{\frac{\pi }{21}}\frac{r^2}{r_3^2}(Y_3^1+Y_3^{-1})
- i2 \sqrt{\frac{\pi }{35}}\frac{r^2}{r_3^2}(Y_3^3+Y_3^{-3})\\ &\varphi_{021}\propto 2\sqrt{\frac{\pi}{3}}\left(1-\frac{2}{5}\frac{r^2}{r_3^2}\right)Y_1^0
- \frac{4}{5}\sqrt{\frac{\pi }{7}}\frac{r^2}{r_3^2}Y_3^0
- 2 \sqrt{\frac{2 \pi }{105}}\frac{r^2}{r_3^2}(Y_3^2+Y_3^{-2})\\ &\varphi_{102}\propto \sqrt{\frac{2\pi}{3}}\left(1-\frac{2}{5}\frac{r^2}{r_3^2}\right)(-Y_1^1+Y_1^{-1})
- \frac{8}{5}\sqrt{\frac{\pi }{21}}\frac{r^2}{r_3^2}(-Y_3^1+Y_3^{-1})\\ &\varphi_{120}\propto \sqrt{\frac{2\pi}{3}}\left(1-\frac{2}{5}\frac{r^2}{r_3^2}\right)(-Y_1^1+Y_1^{-1})
- \frac{2}{5}\sqrt{\frac{\pi }{21}}\frac{r^2}{r_3^2}(-Y_3^1+Y_3^{-1})
- 2 \sqrt{\frac{\pi }{35}}\frac{r^2}{r_3^2}(-Y_3^3+Y_3^{-3})\\ &\varphi_{012}\propto i\sqrt{\frac{2\pi}{3}}\left(1-\frac{2}{5}\frac{r^2}{r_3^2}\right)(Y_1^1+Y_1^{-1})
- i\frac{8}{5}\sqrt{\frac{\pi }{21}}\frac{r^2}{r_3^2}\frac{r^2}{r_3^2}(Y_3^3+Y_3^{-3})\\ &\varphi_{201}\propto 2\sqrt{\frac{\pi}{3}}\left(1-\frac{2}{5}\frac{r^2}{r_3^2}\right)Y_1^0
- \frac{4}{5}\sqrt{\frac{\pi }{7}}\frac{r^2}{r_3^2}Y_3^0
- 2 \sqrt{\frac{2 \pi }{105}}\frac{r^2}{r_3^2}(Y_3^2+Y_3^{-2})\\ &\varphi_{111}\propto i\sqrt{\frac{2 \pi }{105}}\frac{r^2}{r_3^2}(-Y_3^2+Y_3^{-2}) );
のように、 と、 との線形結合で を表せる。